Xrtti::TypeStructure Class Reference
#include <Xrtti.h>
Inheritance diagram for Xrtti::TypeStructure:
Public Member Functions | |
| virtual | ~TypeStructure () |
| bool | operator== (const TypeStructure &other) const |
| bool | operator!= (const TypeStructure &other) const |
| virtual const Structure & | GetStructure () const =0 |
Detailed Description
************************************************************************** TypeStructure represents a C++ type which is a structure (class, struct, or union).Constructor & Destructor Documentation
| virtual Xrtti::TypeStructure::~TypeStructure | ( | ) | [inline, virtual] |
Member Function Documentation
| bool Xrtti::TypeStructure::operator== | ( | const TypeStructure & | other | ) | const |
Equality operator - returns true if this object is "functionally equivalent" to [other]. The two objects don't have to be exactly identical, but do have to be identical in every meaningful way. Note also that this doesn't test for equality of any base class members; it is a test only at this level of the inheritence hierarcy. To test if an object is completely equals, including for all of its subclasses defined in the Xrtti hierarchy, you must cast this class to its most derived class and call that method.
- Parameters:
-
other is the other object to compare against
- Returns:
- true if this object is functionally equal to the other, false if not
| bool Xrtti::TypeStructure::operator!= | ( | const TypeStructure & | other | ) | const [inline] |
Inequality operator - returns false when the == operator would return true, and vice versa.
- Parameters:
-
other is the other object to compare against
- Returns:
- false when the == operator would return true, and vice versa.
| virtual const Structure& Xrtti::TypeStructure::GetStructure | ( | ) | const [pure virtual] |
The documentation for this class was generated from the following file:
